Differential Water Pressure: dP = 5*10^(-5)*L*W^(1.75)/d^1.25 The factor converts pascal to bar. L=length in meters. w = V/A this is the water flow per unit surface. The flow V in liters per second is given from the mass flow M (this Kg per min): M = P/(Cm*dT) [Kg/min] where P the power, P=IR^2 [kW] and Cm = 4187 J/(Kg*K) the water specific heat capacitance. dT=50 C the assumed temperature gradient. Example: -------- I=390A (for the 110 mm gap magnet) R20 = 0.109 Ohm R50 = 0.122 Ohm water resistance for 50 C P = 18.6 kW M = 5.33 Kg/min V = 0.0444 l/s w = 2.26 m/s dP = 22.9 bar This pressure would require modification in the existing cooling.The 10mm gap magnet gives I=290A and dP=8.1 bar which does not require any modifications. --------